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All Numbers Are Equal 6 j1 h: h7 E5 F: ?% X/ T
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then % T, W/ h4 u. G1 D0 Y7 G
# j0 Z5 W. z& M$ b& z
a + b = t' F7 K5 I: J# f. Y8 o
(a + b)(a - b) = t(a - b)! u; ?; D/ E; U
a^2 - b^2 = ta - tb0 S1 ` l, Q/ Q# D
a^2 - ta = b^2 - tb
/ I/ x7 ~1 t! p1 b1 H4 i5 Pa^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
2 O: P' ]4 b- G, E _(a - t/2)^2 = (b - t/2)^2
' c3 }; U! Q5 R3 S) m0 n" p' E/ `a - t/2 = b - t/2
4 X7 I [& b/ H8 F% a4 g# Pa = b
7 x6 x- g4 P& z5 Y y/ b7 \: p/ P m5 w! Q
So all numbers are the same, and math is pointless. |
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