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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置4 l+ h& |) r6 s+ D
2 B# ?9 }4 r' _3 ?: _, O# Y; i' B; T |/ Q p4 S
+ B' H' z( {) c# s
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
$ w, m2 I, }) l8 i3 y }4 ~" `1 x4 \7 O0 k( P2 v
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.9 f9 e- x0 [8 x3 Q/ s
5 k6 K4 H+ Z. s/ D+ T0 h. j7 @% W
Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).7 S" U3 Q$ _7 v4 [6 o
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