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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置' L0 m: O8 s; A) w# K
5 E2 R1 ?9 U" m+ P- \: ], A& A9 s3 q, ~
) ?; K" ?8 @0 c, T
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
, D2 i. F0 p: y& i) z- D0 r
# L6 M# u5 @, \" j* l% `% ?mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.# {) C# m1 _0 \2 e1 e d9 e
0 g/ z3 |9 M5 w/ eCalculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward). A: U) a" Q! Z* t" k( K$ T$ |
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发表于 2012-4-2 21:27
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