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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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) E9 M! A$ q7 ?+ l; k3 d, e m 1# jack_lai
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7 n) U/ m% h( P$ e; W4 t2 D足球看完了来看看题目。
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' e# z4 q& Z+ \4 f# D9 ?% ^% qThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
0 C3 _. b4 k' Q9 x- k uThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
6 y, V3 V$ P& T! c# u+ t: hWe can see it is not easy to install the 22 meters heat trace according as figure 1
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7 }6 x$ J$ v. [+ `0 uAs a normal question we just discuss:- D! ~( B4 `9 @% J |* b
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? - v% }3 e- |. x3 [, u% i
I call this is JACK LAI Spiral Method 螺旋法6 Q" A6 u( p2 C6 ~
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
7 [# M3 B0 v" J# K4 f6 hThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. , y! _9 m6 t+ k z
Because the pipe is horizontal, position 0 can not be placed. See figure 2
! i/ o: l( Y( n) @- r0 ~! C% iBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3- G9 {, D7 z( P3 r( k* s8 K5 @
The total heat trace that can be installed here is about
# k* p7 d9 f: \! ~4 G0 h8 j1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters3 K$ B; ~) M# \- L( j- ^9 [' ]
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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Note :: ~6 x' n3 O4 l/ v
1. The minimum bend radius:+ W- t$ i! I3 |, V. f
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
3 s- [0 R( _/ [ w# I* ~* w5/16 *6 = 30/16 almost = 2 inches
# y( \8 k$ ^: }% q0 H+ C8 | nSo the maximum bend radius is 2 inches.
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As regular 6 H& {4 _7 K3 G) X7 f( c8 C# S+ z
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
) N9 O5 H$ }1 Q M# @( M! Q& e, jif the pipe is horizontal, The length of heat trace can be installed is about
* K4 |* t( `$ ?" N6 m1 * 9 = 9 meters
9 e" k, @% _5 o# yIf the pipe is vertical, The length of heat trace can be installed is about/ D* J8 B+ U9 y
1 * 10 = 10 meters. 9 v- F/ [, v z; p( U- A7 Z/ ^
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe- f7 h% S( t" S# b# z9 n
if the pipe is horizontal , The length of heat trace can be installed is about M% t. B. u8 K1 C5 J8 g0 o
1 * 4 = 4 meters
& o6 p/ X, i4 W4 L2 S5 W! |If the pipe is vertical, The length of heat trace can be installed is about) d( V& }/ c4 S5 I& }+ J; i" }6 D
1 * 5 = 5 meters. |
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