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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 0 g: S; n7 b* f0 D |
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1# jack_lai
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足球看完了来看看题目。. p( Z. ]& i% y
5 L! k$ R% F9 j& E0 o0 w7 {' dThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
% @: a) a+ A$ m5 `" }" K' ZThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)7 r$ y+ K! o/ T& K( n
We can see it is not easy to install the 22 meters heat trace according as figure 1# B, A/ k: @* c4 i% G/ X
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As a normal question we just discuss:0 h9 P: v5 K5 B# F
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 1 N+ p; K1 Q( y7 |% N+ G
I call this is JACK LAI Spiral Method 螺旋法" v/ i$ |' A- M: S* ?# f
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
8 B. _+ f# r/ Q* S! i/ U+ JThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. 8 n2 s0 f" F! Y4 d* o
Because the pipe is horizontal, position 0 can not be placed. See figure 25 \! [, j* F1 @0 R( ?" @: n* l# u
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3+ R3 i: I! C' H9 v' n! D7 }( f
The total heat trace that can be installed here is about ) \4 `" s* G9 y N; T# M+ k
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
& q5 \7 z9 @) ]1 LSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. - l ^: ~: J; `
5 y" p) c2 m2 m) @: ~) D2 iNote :
3 g( ?9 @4 `) W. W% b3 G1. The minimum bend radius:2 g3 S* b* B5 ^! o7 t( L
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
9 L: j& u3 z& p& c1 \6 E5/16 *6 = 30/16 almost = 2 inches$ q. o/ V$ W2 S
So the maximum bend radius is 2 inches.
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As regular + S3 C7 F. K9 O
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
- l2 T; Y, j! j' L8 h) E, B1 u+ ~if the pipe is horizontal, The length of heat trace can be installed is about2 I, e' v6 `7 N1 }' d1 j
1 * 9 = 9 meters% s7 y$ N& O C8 u7 x) k
If the pipe is vertical, The length of heat trace can be installed is about4 v0 e* A" j* f
1 * 10 = 10 meters.
* Q1 C, {% o/ j/ v+ e- NFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
) d" \4 r. l7 K- y: ?+ D; y8 \, Cif the pipe is horizontal , The length of heat trace can be installed is about
% ]& B3 S, b r& W! _) V; ]+ C1 * 4 = 4 meters
+ K% _& @. `+ q4 W% L9 HIf the pipe is vertical, The length of heat trace can be installed is about0 B2 Y$ O' D9 `* v+ q
1 * 5 = 5 meters. |
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