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All Numbers Are Equal # R) p+ D" {0 l( I$ J8 k
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
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a + b = t) @) d$ F* t+ G0 R8 c9 \7 d
(a + b)(a - b) = t(a - b)4 m8 ] B9 ` t7 ^, h
a^2 - b^2 = ta - tb
8 ?, l+ \- y8 M9 K9 |3 [a^2 - ta = b^2 - tb
1 n$ u6 S+ X& _$ Sa^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
0 j3 Z1 w9 {8 |$ k6 f% A' N(a - t/2)^2 = (b - t/2)^2. R% h# \* \2 {* i
a - t/2 = b - t/23 t% b8 ^0 y( J4 i J
a = b * i& T: Y% G& t% ~' \
* O d; S* n. @- \& M* s* B3 {So all numbers are the same, and math is pointless. |
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