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All Numbers Are Equal
4 l8 P+ z: @2 ] iTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then 2 |1 a$ k t4 x: O
: d) [, K: F7 {) ^; va + b = t0 k+ m8 S; y: v( G1 U+ N
(a + b)(a - b) = t(a - b)1 I2 R3 ~4 Y; l4 }- S9 M% R2 D) M
a^2 - b^2 = ta - tb
3 o! G# _+ T7 p1 b8 O, ?: {8 ?/ P& Ra^2 - ta = b^2 - tb
1 A3 D% m7 s0 \0 e! V4 l' s9 Sa^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
7 `8 N# X* {9 J4 V6 M(a - t/2)^2 = (b - t/2)^2
) Y* Q0 k$ B7 V* t- ha - t/2 = b - t/2
7 V, _( Z* C4 n$ Fa = b
, X/ @( P$ M4 x6 P0 o0 n1 Q
" `& ^* w( `; `So all numbers are the same, and math is pointless. |
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