求助一到地球物理的题

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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置

  L/ r1 l  E( \' y3 S3 W6 g1 F* X+ |) |
2 J6 z: m6 T) S9 X6 v& d
  Z: @( n5 n7 S! y- w+ @4 D(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
& C0 T1 q' M: g3 `+ T  R2 Z
3 M; }7 U# g. \3 l. _( ?mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.

: `0 q* N* Z' F2 m0 v# @Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).