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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置' _& m/ [) Z# \: @7 z( m
, J3 m6 O- M9 X5 ^! i
' N+ q e$ x2 D4 L F7 F+ }: G' ^$ |* |+ Z6 A7 ^' z
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
6 R( E" r+ F" \# G/ D5 e- S7 d- z# K( T4 o
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.8 u% J2 a+ S. S0 c7 }
C, }! ?% V/ J* a! x
Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).# O$ h3 N* f1 k0 Y: U
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